What is the answer to 2^x=2000 ?

The answer to 2^x=2000 is x=(ln(2000))/(ln(2))

Solve for x: 2^x=2000

The solution is x=(ln(2000))/(ln(2))

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2^{x} = 2000

x = \frac{ln ( 2000 )}{ln ( 2 )}

Decimal Notation

x = 10.96578 \dots

Solution steps

2^{x} = 2000

Apply exponent rules

x ln (2) = ln (2000)

Solve

x ln (2) = ln (2000) : x = \frac{ln ( 2000 )}{ln ( 2 )}

x = \frac{ln ( 2000 )}{ln ( 2 )}

e^{8 y} = 2

2^{4} \cdot 4^{2} = 1 6^{x}

81 \cdot 9^{- 2 x - 2} = 27

5 \cdot 1 0^{\frac{x}{4}} = 32

x + e^{x} = 0, x