What are the solutions to the equation s^2-4s+5=0 ?

The solutions to the equation s^2-4s+5=0 are s=2+i,s=2-i

Find the zeros of s^2-4s+5=0

The zeros of s^2-4s+5=0 are s=2+i,s=2-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

s^{2} - 4 s + 5 = 0

s = 2 + i, s = 2 - i

Solution steps

s^{2} - 4 s + 5 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 5 : 2 i

s_{1, 2} = \frac{- ( - 4 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 4 ) + 2 i}{2 \cdot 1}, s_{2} = \frac{- ( - 4 ) - 2 i}{2 \cdot 1}

s = \frac{- ( - 4 ) + 2 i}{2 \cdot 1} : 2 + i

s = \frac{- ( - 4 ) - 2 i}{2 \cdot 1} : 2 - i

The solutions to the quadratic equation are:

s = 2 + i, s = 2 - i

810 + 240 - 250

x^{2} - 16 x + 60

7 x - 10 = x + 2

3 6^{2} + 1 5^{2} = c^{2}

\frac{3}{2} \cdot \frac{3}{2}

What are the solutions to the equation s^2-4s+5=0 ?
The solutions to the equation s^2-4s+5=0 are s=2+i,s=2-i
Find the zeros of s^2-4s+5=0
The zeros of s^2-4s+5=0 are s=2+i,s=2-i