What is the answer to 5^{x^2-7x+9}= 1/125 ?

The answer to 5^{x^2-7x+9}= 1/125 is x=4,x=3

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5^{x^2-7x+9}= 1/125

5^{x^{2} - 7 x + 9} = \frac{1}{125}

x = 4, x = 3

Solution steps

5^{x^{2} - 7 x + 9} = \frac{1}{125}

Apply exponent rules

x^{2} - 7 x + 9 = - 3

Solve

x^{2} - 7 x + 9 = - 3 : x = 4, x = 3

x = 4, x = 3

(\frac{1}{2})^{x^{2 - 3}} = 4

25 = 0.2 5^{x}

e^{- x} x - 2 e^{- x} = 0

1 2^{t} = 24

1 6^{x + 7} = 4^{x + 3} \cdot 6 4^{5}

What is the answer to 5^{x^2-7x+9}= 1/125 ?
The answer to 5^{x^2-7x+9}= 1/125 is x=4,x=3
Solve for x: 5^{x^2-7x+9}= 1/125
The solution is x=4,x=3