What is the answer to 7^{2x+3}=42 ?

The answer to 7^{2x+3}=42 is x=(ln(6/49))/(2ln(7))

Solve for x: 7^{2x+3}=42

The solution is x=(ln(6/49))/(2ln(7))

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7^{2 x + 3} = 42

x = \frac{ln ( \frac{6}{49} )}{2 ln ( 7 )}

Decimal Notation

x = - 0.53960 \dots

Solution steps

7^{2 x + 3} = 42

Apply exponent rules

(2 x + 3) ln (7) = ln (42)

Solve

(2 x + 3) ln (7) = ln (42) : x = \frac{ln ( \frac{6}{49} )}{2 ln ( 7 )}

x = \frac{ln ( \frac{6}{49} )}{2 ln ( 7 )}

2^{5 x - 4} = 10

10 (4)^{x} = 20 (6)^{3 x}

10 0^{x} = 100000

y, a = v t^{x} (1 + k^{y - x})

8^{4 p} = 8^{4 p + 12}

What is the answer to 7^{2x+3}=42 ?
The answer to 7^{2x+3}=42 is x=(ln(6/49))/(2ln(7))
Solve for x: 7^{2x+3}=42
The solution is x=(ln(6/49))/(2ln(7))