What is the answer to 2^{x+1}+2^{x+3}-40=0 ?

The answer to 2^{x+1}+2^{x+3}-40=0 is x=2

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2^{x+1}+2^{x+3}-40=0

2^{x + 1} + 2^{x + 3} - 40 = 0

x = 2

Solution steps

2^{x + 1} + 2^{x + 3} - 40 = 0

Factor

2^{x + 1} + 2^{x + 3} - 40 : 10 (2^{x} - 4)

10 (2^{x} - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2^{x} - 4 = 0

Solve

2^{x} - 4 = 0 : x = 2

x = 2

6 4^{2^{1 - x}} = 8^{2^{x + 1}}

x^{2} e^{x} - x e^{x} - 2 e^{x} = 0

2^{∣ A ∣} = 2^{4}

2^{n - 3} = 8^{n}

2 7^{2} = 3^{x}

What is the answer to 2^{x+1}+2^{x+3}-40=0 ?
The answer to 2^{x+1}+2^{x+3}-40=0 is x=2
Solve for x: 2^{x+1}+2^{x+3}-40=0
The solution is x=2