What are the solutions to the equation 2x^2=32 ?

The solutions to the equation 2x^2=32 are x=4,x=-4

Find the zeros of 2x^2=32

The zeros of 2x^2=32 are x=4,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} = 32

x = 4, x = - 4

Solution steps

2 x^{2} = 32

Divide both sides by

2

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

29 x + 92 = 29 x - 11

\frac{7}{8} \div (\frac{5}{12} + \frac{7}{8})

13 x - 4 = 8 + x

6 + 3 i

\frac{( 2 )}{\frac{2}{3}} - \frac{( \frac{2}{3} )}{2}

What are the solutions to the equation 2x^2=32 ?
The solutions to the equation 2x^2=32 are x=4,x=-4
Find the zeros of 2x^2=32
The zeros of 2x^2=32 are x=4,x=-4