What is the answer to 27^{4x}=9^{x+1} ?

The answer to 27^{4x}=9^{x+1} is x= 1/5

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27^{4x}=9^{x+1}

2 7^{4 x} = 9^{x + 1}

x = \frac{1}{5}

Decimal Notation

x = 0.2

Solution steps

2 7^{4 x} = 9^{x + 1}

Apply exponent rules

12 x = 2 (x + 1)

Solve

12 x = 2 (x + 1) : x = \frac{1}{5}

x = \frac{1}{5}

e^{x + 5} = 3

1.1 5^{104} = 1.0 2^{x}

\frac{n + 4}{3 ^{n}} = \frac{2}{3}

2^{x} \cdot 8^{- x} = 4^{x}

2 = e^{x + 3}