What is the answer to 2^{x-3}=7 ?

The answer to 2^{x-3}=7 is x=(ln(7))/(ln(2))+3

Solve for x: 2^{x-3}=7

The solution is x=(ln(7))/(ln(2))+3

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2^{x - 3} = 7

x = \frac{ln ( 7 )}{ln ( 2 )} + 3

Decimal Notation

x = 5.80735 \dots

Solution steps

2^{x - 3} = 7

Apply exponent rules

(x - 3) ln (2) = ln (7)

Solve

(x - 3) ln (2) = ln (7) : x = \frac{ln ( 7 )}{ln ( 2 )} + 3

x = \frac{ln ( 7 )}{ln ( 2 )} + 3

70 = 120 e^{2 k} + 25

2 e^{- x} x - e^{- x} (x^{2} - 3) = 0

0 = e^{x} - 4

7^{x} \cdot 49 = 4 9^{x}

(2)^{x} = 32

What is the answer to 2^{x-3}=7 ?
The answer to 2^{x-3}=7 is x=(ln(7))/(ln(2))+3
Solve for x: 2^{x-3}=7
The solution is x=(ln(7))/(ln(2))+3