What is the answer to 5^x=2^{x+3} ?

The answer to 5^x=2^{x+3} is x=(3ln(2))/(ln(5)-ln(2))

Solve for x: 5^x=2^{x+3}

The solution is x=(3ln(2))/(ln(5)-ln(2))

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5^{x} = 2^{x + 3}

x = \frac{3 ln ( 2 )}{ln ( 5 ) - ln ( 2 )}

Decimal Notation

x = 2.26941 \dots

Solution steps

5^{x} = 2^{x + 3}

Apply exponent rules

x ln (5) = (x + 3) ln (2)

Solve

x ln (5) = (x + 3) ln (2) : x = \frac{3 ln ( 2 )}{ln ( 5 ) - ln ( 2 )}

x = \frac{3 ln ( 2 )}{ln ( 5 ) - ln ( 2 )}

4^{x} + 2^{x} - 2 = 0

21 6^{x} = 26

9^{8 x - 7} = 1

4 \cdot 2^{x} = 2 x \cdot 2^{x}

2^{x} \cdot 3^{x - 1} = 72

What is the answer to 5^x=2^{x+3} ?
The answer to 5^x=2^{x+3} is x=(3ln(2))/(ln(5)-ln(2))
Solve for x: 5^x=2^{x+3}
The solution is x=(3ln(2))/(ln(5)-ln(2))