What is the answer to 3^{x-2}=11 ?

The answer to 3^{x-2}=11 is x=(ln(11))/(ln(3))+2

Solve for x: 3^{x-2}=11

The solution is x=(ln(11))/(ln(3))+2

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3^{x - 2} = 11

x = \frac{ln ( 11 )}{ln ( 3 )} + 2

Decimal Notation

x = 4.18265 \dots

Solution steps

3^{x - 2} = 11

Apply exponent rules

(x - 2) ln (3) = ln (11)

Solve

(x - 2) ln (3) = ln (11) : x = \frac{ln ( 11 )}{ln ( 3 )} + 2

x = \frac{ln ( 11 )}{ln ( 3 )} + 2

x, 3^{x} = \frac{1}{81}

x, y^{2} = e^{2 x} + 2 x + c

2 5^{x} + 2 5^{x} = 0.4

45 = 220 (0.5)^{x} + 20

65 = 2 5^{x}

What is the answer to 3^{x-2}=11 ?
The answer to 3^{x-2}=11 is x=(ln(11))/(ln(3))+2
Solve for x: 3^{x-2}=11
The solution is x=(ln(11))/(ln(3))+2