What is the answer to 7^{3x-4}=14 ?

The answer to 7^{3x-4}=14 is x=(ln(14)+4ln(7))/(3ln(7))

Solve for x: 7^{3x-4}=14

The solution is x=(ln(14)+4ln(7))/(3ln(7))

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7^{3 x - 4} = 14

x = \frac{ln ( 14 ) + 4 ln ( 7 )}{3 ln ( 7 )}

Decimal Notation

x = 1.78540 \dots

Solution steps

7^{3 x - 4} = 14

Apply exponent rules

(3 x - 4) ln (7) = ln (14)

Solve

(3 x - 4) ln (7) = ln (14) : x = \frac{ln ( 14 ) + 4 ln ( 7 )}{3 ln ( 7 )}

x = \frac{ln ( 14 ) + 4 ln ( 7 )}{3 ln ( 7 )}

0 = - e^{- x}

5 (2)^{x} = 1 0^{x}

2^{3 x - 1} = 3^{x + 2}

250 e^{0.06 t} = 250, t

4^{2 x^{2} - 11 x + 15} = 1

What is the answer to 7^{3x-4}=14 ?
The answer to 7^{3x-4}=14 is x=(ln(14)+4ln(7))/(3ln(7))
Solve for x: 7^{3x-4}=14
The solution is x=(ln(14)+4ln(7))/(3ln(7))