What is the answer to 4(3^x)=3(6^{(3x-3)}) ?

The answer to 4(3^x)=3(6^{(3x-3)}) is x=(ln(288))/(ln(72))

Solve for x: 4(3^x)=3(6^{(3x-3)})

The solution is x=(ln(288))/(ln(72))

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4 (3^{x}) = 3 (6^{(3 x - 3)})

x = \frac{ln ( 288 )}{ln ( 72 )}

Decimal Notation

x = 1.32415 \dots

Solution steps

4 (3^{x}) = 3 (6^{(3 x - 3)})

Apply exponent rules

ln (4) + x ln (3) = ln (3) + (3 x - 3) ln (6)

Solve

ln (4) + x ln (3) = ln (3) + (3 x - 3) ln (6) : x = \frac{ln ( 288 )}{ln ( 72 )}

x = \frac{ln ( 288 )}{ln ( 72 )}

71 = 2 7^{x}

4^{- 3 t} = 0.1

4^{(2 x + 1)} = 1024

3^{x} = e^{x + 2}

62 5^{x - 2} = 12 5^{x + 3}

What is the answer to 4(3^x)=3(6^{(3x-3)}) ?
The answer to 4(3^x)=3(6^{(3x-3)}) is x=(ln(288))/(ln(72))
Solve for x: 4(3^x)=3(6^{(3x-3)})
The solution is x=(ln(288))/(ln(72))