What is the answer to 2^{2x-1}=3^x ?

The answer to 2^{2x-1}=3^x is x=(ln(2))/(2ln(2)-ln(3))

Solve for x: 2^{2x-1}=3^x

The solution is x=(ln(2))/(2ln(2)-ln(3))

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2^{2 x - 1} = 3^{x}

x = \frac{ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

Decimal Notation

x = 2.40942 \dots

Solution steps

2^{2 x - 1} = 3^{x}

Apply exponent rules

(2 x - 1) ln (2) = x ln (3)

Solve

(2 x - 1) ln (2) = x ln (3) : x = \frac{ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

x = \frac{ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

x, 4^{2 x} = 8^{x} (2)

9^{x^{2} + 2} = 2 7^{2 x}

1.0 9^{x} = 2

2^{x^{2}} = 64

lo g_{8} (1 4^{x - 3}) = 13

What is the answer to 2^{2x-1}=3^x ?
The answer to 2^{2x-1}=3^x is x=(ln(2))/(2ln(2)-ln(3))
Solve for x: 2^{2x-1}=3^x
The solution is x=(ln(2))/(2ln(2)-ln(3))