What is the answer to 4x^2(2^x)-9(2^x)=0 ?

The answer to 4x^2(2^x)-9(2^x)=0 is x=-3/2 ,x= 3/2

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4x^2(2^x)-9(2^x)=0

4 x^{2} (2^{x}) - 9 (2^{x}) = 0

x = - \frac{3}{2}, x = \frac{3}{2}

Decimal Notation

x = - 1.5, x = 1.5

Solution steps

4 x^{2} (2^{x}) - 9 (2^{x}) = 0

Factor

4 x^{2} \cdot 2^{x} - 9 \cdot 2^{x} : 2^{x} (2 x + 3) (2 x - 3)

2^{x} (2 x + 3) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2^{x} = 0 or 2 x + 3 = 0 or 2 x - 3 = 0

Solve

2^{x} = 0 :

No Solution for

x \in R

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

2 x - 3 = 0 : x = \frac{3}{2}

x = - \frac{3}{2}, x = \frac{3}{2}

0 = e^{x - 4} + 2.5 x - 11.7

2 \cdot 3^{x} - 5 \cdot 3^{x - 1} = 3

e^{6 x} = 14

e^{6 x} = 15

e^{3 x} = 403.43

What is the answer to 4x^2(2^x)-9(2^x)=0 ?
The answer to 4x^2(2^x)-9(2^x)=0 is x=-3/2 ,x= 3/2
Solve for x: 4x^2(2^x)-9(2^x)=0
The solution is x=-3/2 ,x= 3/2