What is the answer to 3^{(x+1)}=2^{3x} ?

The answer to 3^{(x+1)}=2^{3x} is x=(ln(3))/(3ln(2)-ln(3))

Solve for x: 3^{(x+1)}=2^{3x}

The solution is x=(ln(3))/(3ln(2)-ln(3))

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3^{(x + 1)} = 2^{3 x}

x = \frac{ln ( 3 )}{3 ln ( 2 ) - ln ( 3 )}

Decimal Notation

x = 1.12008 \dots

Solution steps

3^{(x + 1)} = 2^{3 x}

Apply exponent rules

(x + 1) ln (3) = 3 x ln (2)

Solve

(x + 1) ln (3) = 3 x ln (2) : x = \frac{ln ( 3 )}{3 ln ( 2 ) - ln ( 3 )}

x = \frac{ln ( 3 )}{3 ln ( 2 ) - ln ( 3 )}

e^{l n (6 x)} = 19

(\frac{3}{4})^{x} = \frac{16}{9}

2^{x} + 2^{x + 3} = 48

e^{x} + 45 e^{- x} = 14

4 (\frac{1}{3})^{x} = 324

What is the answer to 3^{(x+1)}=2^{3x} ?
The answer to 3^{(x+1)}=2^{3x} is x=(ln(3))/(3ln(2)-ln(3))
Solve for x: 3^{(x+1)}=2^{3x}
The solution is x=(ln(3))/(3ln(2)-ln(3))