What is the answer to (2^{x^2})/(2^{x+6)}=1 ?

The answer to (2^{x^2})/(2^{x+6)}=1 is x=-2,x=3

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(2^{x^2})/(2^{x+6)}=1

\frac{2 ^{x^{2}}}{2 ^{x + 6}} = 1

x = - 2, x = 3

Solution steps

\frac{2 ^{x^{2}}}{2 ^{x + 6}} = 1

Apply exponent rules

(x^{2} - x - 6) ln (2) = ln (1)

Solve

(x^{2} - x - 6) ln (2) = ln (1) : x = - 2, x = 3

x = - 2, x = 3

Verify Solutions:

x = - 2

True

, x = 3

True

The solutions are

x = - 2, x = 3

3 \cdot 2^{4 x} + 2^{2 x} - 10 = 0

8^{3 x - 5} = 4^{x + 3}

\frac{x}{e ^{3 - 2 x}} = 4

y, x = 6^{y}

x 2^{3 x - 1} = 4^{x}

What is the answer to (2^{x^2})/(2^{x+6)}=1 ?
The answer to (2^{x^2})/(2^{x+6)}=1 is x=-2,x=3
Solve for x: (2^{x^2})/(2^{x+6)}=1
The solution is x=-2,x=3