What is the answer to 4^{3x+1}=6^{1-2x} ?

The answer to 4^{3x+1}=6^{1-2x} is x=(ln(3/2))/(2ln(48))

Solve for x: 4^{3x+1}=6^{1-2x}

The solution is x=(ln(3/2))/(2ln(48))

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4^{3 x + 1} = 6^{1 - 2 x}

x = \frac{ln ( \frac{3}{2} )}{2 ln ( 48 )}

Decimal Notation

x = 0.05236 \dots

Solution steps

4^{3 x + 1} = 6^{1 - 2 x}

Apply exponent rules

(3 x + 1) ln (4) = (1 - 2 x) ln (6)

Solve

(3 x + 1) ln (4) = (1 - 2 x) ln (6) : x = \frac{ln ( \frac{3}{2} )}{2 ln ( 48 )}

x = \frac{ln ( \frac{3}{2} )}{2 ln ( 48 )}

5^{x - 9} = 3

1.0 9^{x} = 1.5

4^{- 3 v - 2} = 4^{- v}

e^{12 x} = 2

4 = \frac{1}{2} e^{- 1.2 x}

What is the answer to 4^{3x+1}=6^{1-2x} ?
The answer to 4^{3x+1}=6^{1-2x} is x=(ln(3/2))/(2ln(48))
Solve for x: 4^{3x+1}=6^{1-2x}
The solution is x=(ln(3/2))/(2ln(48))