What is the answer to 3*5^{(x+1)}=7*4^x ?

The answer to 3*5^{(x+1)}=7*4^x is x=(ln(7)-ln(15))/(ln(5)-2ln(2))

Solve for x: 3*5^{(x+1)}=7*4^x

The solution is x=(ln(7)-ln(15))/(ln(5)-2ln(2))

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3 \cdot 5^{(x + 1)} = 7 \cdot 4^{x}

x = \frac{ln ( 7 ) - ln ( 15 )}{ln ( 5 ) - 2 ln ( 2 )}

Decimal Notation

x = - 3.41546 \dots

Solution steps

3 \cdot 5^{(x + 1)} = 7 \cdot 4^{x}

Apply exponent rules

ln (3) + (x + 1) ln (5) = ln (7) + x ln (4)

Solve

ln (3) + (x + 1) ln (5) = ln (7) + x ln (4) : x = \frac{ln ( 7 ) - ln ( 15 )}{ln ( 5 ) - 2 ln ( 2 )}

x = \frac{ln ( 7 ) - ln ( 15 )}{ln ( 5 ) - 2 ln ( 2 )}

3^{4 x} = 2 7^{x + 3}

27.5 = 55 e^{- 0.0036 t}

4^{5 x - 2} = \frac{1}{4 ^{6}}

2^{3 x + 9} = 3 2^{3 x + 1}

- 3.3 \cdot 1 7^{- 4 v} = - 78

What is the answer to 3*5^{(x+1)}=7*4^x ?
The answer to 3*5^{(x+1)}=7*4^x is x=(ln(7)-ln(15))/(ln(5)-2ln(2))
Solve for x: 3*5^{(x+1)}=7*4^x
The solution is x=(ln(7)-ln(15))/(ln(5)-2ln(2))