What is the answer to 3^{x+1}+4=10 ?

The answer to 3^{x+1}+4=10 is x=(ln(6))/(ln(3))-1

Solve for x: 3^{x+1}+4=10

The solution is x=(ln(6))/(ln(3))-1

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3^{x + 1} + 4 = 10

x = \frac{ln ( 6 )}{ln ( 3 )} - 1

Decimal Notation

x = 0.63092 \dots

Solution steps

3^{x + 1} + 4 = 10

Move

4

to the right side

3^{x + 1} = 6

Apply exponent rules

(x + 1) ln (3) = ln (6)

Solve

(x + 1) ln (3) = ln (6) : x = \frac{ln ( 6 )}{ln ( 3 )} - 1

x = \frac{ln ( 6 )}{ln ( 3 )} - 1

2^{x + 3} + 2^{x - 1} = 17

a^{2 x} = e^{3}

\frac{70}{1 + e ^{- x}} = 2

x, 2^{y} = 1 6^{x - 3}

2^{x} \cdot \frac{1}{32} = 32

What is the answer to 3^{x+1}+4=10 ?
The answer to 3^{x+1}+4=10 is x=(ln(6))/(ln(3))-1
Solve for x: 3^{x+1}+4=10
The solution is x=(ln(6))/(ln(3))-1