What is the answer to 4^{x+1}=3 ?

The answer to 4^{x+1}=3 is x=(ln(3))/(2ln(2))-1

Solve for x: 4^{x+1}=3

The solution is x=(ln(3))/(2ln(2))-1

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4^{x + 1} = 3

x = \frac{ln ( 3 )}{2 ln ( 2 )} - 1

Decimal Notation

x = - 0.20751 \dots

Solution steps

4^{x + 1} = 3

Apply exponent rules

(x + 1) ln (4) = ln (3)

Solve

(x + 1) ln (4) = ln (3) : x = \frac{ln ( 3 )}{2 ln ( 2 )} - 1

x = \frac{ln ( 3 )}{2 ln ( 2 )} - 1

1 2^{x - 2} = 20

4 9^{x} - 8 \cdot 7^{x} + 7 = 0

0.9765625 = 500 (2)^{n - 1}

0.0 1^{(3 x - 1)} = 0.0 1^{0} AA

4^{- 2 x} = 64

What is the answer to 4^{x+1}=3 ?
The answer to 4^{x+1}=3 is x=(ln(3))/(2ln(2))-1
Solve for x: 4^{x+1}=3
The solution is x=(ln(3))/(2ln(2))-1