What is the answer to 2^{x-4}=3^{2x-1} ?

The answer to 2^{x-4}=3^{2x-1} is x=(-ln(3)+4ln(2))/(ln(2)-2ln(3))

Solve for x: 2^{x-4}=3^{2x-1}

The solution is x=(-ln(3)+4ln(2))/(ln(2)-2ln(3))

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2^{x - 4} = 3^{2 x - 1}

x = \frac{- ln ( 3 ) + 4 ln ( 2 )}{ln ( 2 ) - 2 ln ( 3 )}

Decimal Notation

x = - 1.11295 \dots

Solution steps

2^{x - 4} = 3^{2 x - 1}

Apply exponent rules

(x - 4) ln (2) = (2 x - 1) ln (3)

Solve

(x - 4) ln (2) = (2 x - 1) ln (3) : x = \frac{- ln ( 3 ) + 4 ln ( 2 )}{ln ( 2 ) - 2 ln ( 3 )}

x = \frac{- ln ( 3 ) + 4 ln ( 2 )}{ln ( 2 ) - 2 ln ( 3 )}

3^{x + 1} + 3^{x} + 3^{x + 2} = 117

7^{x + 1} = 343

5^{x} = 615

4^{2 x} - 3 (4^{x}) = - 2

x^{0.2} = 2^{x}

What is the answer to 2^{x-4}=3^{2x-1} ?
The answer to 2^{x-4}=3^{2x-1} is x=(-ln(3)+4ln(2))/(ln(2)-2ln(3))
Solve for x: 2^{x-4}=3^{2x-1}
The solution is x=(-ln(3)+4ln(2))/(ln(2)-2ln(3))