What is the answer to 2=(1+0.1)^t ?

The answer to 2=(1+0.1)^t is t=(ln(2))/(ln(1.1))

Solve for t: 2=(1+0.1)^t

The solution is t=(ln(2))/(ln(1.1))

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2 = (1 + 0.1)^{t}

t = \frac{ln ( 2 )}{ln ( 1.1 )}

Decimal Notation

t = 7.27254 \dots

Solution steps

2 = (1 + 0.1)^{t}

Apply exponent rules

ln (2) = t ln (1 + 0.1)

Solve

ln (2) = t ln (1 + 0.1) : t = \frac{ln ( 2 )}{ln ( 1.1 )}

t = \frac{ln ( 2 )}{ln ( 1.1 )}

3 6^{4} = 6^{3 x + 2}

x, 1 = a e^{- b x}

10 = 80000 (0.85)^{x}

3 \cdot 2^{x + 1} - 64 = 0

3^{x - 2} = 3^{17}

What is the answer to 2=(1+0.1)^t ?
The answer to 2=(1+0.1)^t is t=(ln(2))/(ln(1.1))
Solve for t: 2=(1+0.1)^t
The solution is t=(ln(2))/(ln(1.1))