What is the answer to 9^x=(1/3)^{x^2-x} ?

The answer to 9^x=(1/3)^{x^2-x} is x=-1,x=0

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9^x=(1/3)^{x^2-x}

9^{x} = (\frac{1}{3})^{x^{2} - x}

x = - 1, x = 0

Solution steps

9^{x} = (\frac{1}{3})^{x^{2} - x}

Apply exponent rules

2 x = - (x^{2} - x)

Solve

2 x = - (x^{2} - x) : x = - 1, x = 0

x = - 1, x = 0

- 1^{x} = 1

3^{x} + 4 \cdot 3^{x + 1} = 13

e^{3 x} = 2 (e^{x})

x e^{2 x} + 3 e x^{2} e^{2 x} = 0

1.0 5^{t} = 4.35

What is the answer to 9^x=(1/3)^{x^2-x} ?
The answer to 9^x=(1/3)^{x^2-x} is x=-1,x=0
Solve for x: 9^x=(1/3)^{x^2-x}
The solution is x=-1,x=0