What is the answer to 3^{x+2}=5^{2x-1} ?

The answer to 3^{x+2}=5^{2x-1} is x=(ln(45))/(2ln(5)-ln(3))

Solve for x: 3^{x+2}=5^{2x-1}

The solution is x=(ln(45))/(2ln(5)-ln(3))

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3^{x + 2} = 5^{2 x - 1}

x = \frac{ln ( 45 )}{2 ln ( 5 ) - ln ( 3 )}

Decimal Notation

x = 1.79537 \dots

Solution steps

3^{x + 2} = 5^{2 x - 1}

Apply exponent rules

(x + 2) ln (3) = (2 x - 1) ln (5)

Solve

(x + 2) ln (3) = (2 x - 1) ln (5) : x = \frac{ln ( 45 )}{2 ln ( 5 ) - ln ( 3 )}

x = \frac{ln ( 45 )}{2 ln ( 5 ) - ln ( 3 )}

e^{b} = 46

3^{2 x + 1} = 4^{x - 2}

1.3345 = e^{7.25 x}

2^{x + 3} = 0

5^{2 x} + 125 = 6 \cdot 5^{x + 1}

What is the answer to 3^{x+2}=5^{2x-1} ?
The answer to 3^{x+2}=5^{2x-1} is x=(ln(45))/(2ln(5)-ln(3))
Solve for x: 3^{x+2}=5^{2x-1}
The solution is x=(ln(45))/(2ln(5)-ln(3))