What is the answer to 3^{3x+4}=12 ?

The answer to 3^{3x+4}=12 is x=(ln(4/27))/(3ln(3))

Solve for x: 3^{3x+4}=12

The solution is x=(ln(4/27))/(3ln(3))

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3^{3 x + 4} = 12

x = \frac{ln ( \frac{4}{27} )}{3 ln ( 3 )}

Decimal Notation

x = - 0.57938 \dots

Solution steps

3^{3 x + 4} = 12

Apply exponent rules

(3 x + 4) ln (3) = ln (12)

Solve

(3 x + 4) ln (3) = ln (12) : x = \frac{ln ( \frac{4}{27} )}{3 ln ( 3 )}

x = \frac{ln ( \frac{4}{27} )}{3 ln ( 3 )}

x, 2^{x} = 32

1 7^{x + 2} = 4

384 e^{8} = 2^{x}

3^{- 8 x} = 9^{3 - 3 x}

4 \cdot 3^{2 x} + 8 \cdot 3^{x} - 5 = 0

What is the answer to 3^{3x+4}=12 ?
The answer to 3^{3x+4}=12 is x=(ln(4/27))/(3ln(3))
Solve for x: 3^{3x+4}=12
The solution is x=(ln(4/27))/(3ln(3))