What is the answer to 3^x*4^{(2x+1)}=6^{x+2} ?

The answer to 3^x*4^{(2x+1)}=6^{x+2} is x=(2ln(3))/(3ln(2))

Solve for x: 3^x*4^{(2x+1)}=6^{x+2}

The solution is x=(2ln(3))/(3ln(2))

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3^{x} \cdot 4^{(2 x + 1)} = 6^{x + 2}

x = \frac{2 ln ( 3 )}{3 ln ( 2 )}

Decimal Notation

x = 1.05664 \dots

Solution steps

3^{x} \cdot 4^{(2 x + 1)} = 6^{x + 2}

Apply exponent rules

(x + lo g_{3} (4) (2 x + 1)) ln (3) = (x + 2) ln (6)

Solve

(x + lo g_{3} (4) (2 x + 1)) ln (3) = (x + 2) ln (6) : x = \frac{2 ln ( 3 )}{3 ln ( 2 )}

x = \frac{2 ln ( 3 )}{3 ln ( 2 )}

e^{- 2 x} - 3 e^{- x} = - 2

100000 = 50000 \cdot (1 + 0.04)^{n}

10 e^{6 x} = 5 e^{- 3 x}

8 1^{x} = 2 7^{- x}

What is the answer to 3^x*4^{(2x+1)}=6^{x+2} ?
The answer to 3^x*4^{(2x+1)}=6^{x+2} is x=(2ln(3))/(3ln(2))
Solve for x: 3^x*4^{(2x+1)}=6^{x+2}
The solution is x=(2ln(3))/(3ln(2))