What is the answer to 34*1.125^t=143 ?

The answer to 34*1.125^t=143 is t=(ln(143/34))/(ln(1.125))

Solve for t: 34*1.125^t=143

The solution is t=(ln(143/34))/(ln(1.125))

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34 \cdot 1.12 5^{t} = 143

t = \frac{ln ( \frac{143}{34} )}{ln ( 1.125 )}

Decimal Notation

t = 12.19601 \dots

Solution steps

34 \cdot 1.12 5^{t} = 143

Divide both sides by

34

1.12 5^{t} = \frac{143}{34}

Apply exponent rules

t ln (1.125) = ln (\frac{143}{34})

Solve

t ln (1.125) = ln (\frac{143}{34}) : t = \frac{ln ( \frac{143}{34} )}{ln ( 1.125 )}

t = \frac{ln ( \frac{143}{34} )}{ln ( 1.125 )}

x, 2^{x - 5} = 5

180 = 16.56 (1.078)^{t} + 97

2^{x - 4} = 3

e^{x} x^{2} - 2 e^{x} = 0

(2^{2})^{3} = 8^{x}

What is the answer to 34*1.125^t=143 ?
The answer to 34*1.125^t=143 is t=(ln(143/34))/(ln(1.125))
Solve for t: 34*1.125^t=143
The solution is t=(ln(143/34))/(ln(1.125))