What is the answer to 8^{3x}=\sqrt[3]{2^{9x}} ?

The answer to 8^{3x}=\sqrt[3]{2^{9x}} is x=0

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8^{3x}=\sqrt[3]{2^{9x}}

x = 0

Solution steps

Apply exponent rules

9 x = 3 x

Solve

9 x = 3 x : x = 0

x = 0

x, a^{x} = k b^{x}

61 = 3 5^{x}

8 e^{7.5 x + 9} + 2.5 = 32

9^{x} = 2 7^{82}

8^{y} \cdot 4^{y^{2} - 8} = 16

What is the answer to 8^{3x}=\sqrt[3]{2^{9x}} ?
The answer to 8^{3x}=\sqrt[3]{2^{9x}} is x=0
Solve for x: 8^{3x}=\sqrt[3]{2^{9x}}
The solution is x=0