What is 2sqrt(3-x)*4\sqrt[3]{3-x} ?

The solution to 2sqrt(3-x)*4\sqrt[3]{3-x} is 8\sqrt[6]{(3-x)^5}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 2sqrt(3-x)*4\sqrt[3]{3-x}

simplify

Solution steps

Multiply the numbers:

2 \cdot 4 = 8

3 - x = (3 - x)^{\frac{1}{2}}

= 8 (3 - x)^{\frac{1}{2}} (3 - x)^{\frac{1}{3}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

(3 - x)^{\frac{1}{2}} (3 - x)^{\frac{1}{3}} = (3 - x)^{\frac{1}{2} + \frac{1}{3}}

= 8 (3 - x)^{\frac{1}{2} + \frac{1}{3}}

\frac{1}{2} + \frac{1}{3} = \frac{5}{6}

= 8 (3 - x)^{\frac{5}{6}}

2 x^{2} - 11 x + 12

0 = - 5 p^{2} + 110 p - 605

- 2 (\frac{1}{3}) - 1

2 m^{2} + 7 m + 6

\frac{8 ^{3}}{8}

What is 2sqrt(3-x)*4\sqrt[3]{3-x} ?
The solution to 2sqrt(3-x)*4\sqrt[3]{3-x} is 8\sqrt[6]{(3-x)^5}