What is the answer to 7^x=35 ?

The answer to 7^x=35 is x=(ln(35))/(ln(7))

The solution is x=(ln(35))/(ln(7))

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7^x=35

7^{x} = 35

x = \frac{ln ( 35 )}{ln ( 7 )}

Decimal Notation

x = 1.82708 \dots

Solution steps

7^{x} = 35

Apply exponent rules

x ln (7) = ln (35)

Solve

x ln (7) = ln (35) : x = \frac{ln ( 35 )}{ln ( 7 )}

x = \frac{ln ( 35 )}{ln ( 7 )}

3^{x} = 144

a, m^{a + 1} = 0.5

8 \cdot 2^{x} = 4

4^{x + 2} = 8^{2 x}

7 (7^{2 x}) + 20 (7^{x}) - 3 = 0