What is the answer to 2^{2x-3}=5^{1-x} ?

The answer to 2^{2x-3}=5^{1-x} is x=(ln(40))/(ln(20))

Solve for x: 2^{2x-3}=5^{1-x}

The solution is x=(ln(40))/(ln(20))

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2^{2 x - 3} = 5^{1 - x}

x = \frac{ln ( 40 )}{ln ( 20 )}

Decimal Notation

x = 1.23137 \dots

Solution steps

2^{2 x - 3} = 5^{1 - x}

Apply exponent rules

(2 x - 3) ln (2) = (1 - x) ln (5)

Solve

(2 x - 3) ln (2) = (1 - x) ln (5) : x = \frac{ln ( 40 )}{ln ( 20 )}

x = \frac{ln ( 40 )}{ln ( 20 )}

5^{x - 1} = 8^{x + 1}

9^{X} - 6 \cdot 3^{X} - 81 = 0

25 (12 5^{x}) = 1

64 = (4)^{y}

4 x (c e^{- 2 x^{2}}) = 0

What is the answer to 2^{2x-3}=5^{1-x} ?
The answer to 2^{2x-3}=5^{1-x} is x=(ln(40))/(ln(20))
Solve for x: 2^{2x-3}=5^{1-x}
The solution is x=(ln(40))/(ln(20))