What is the answer to (2^{x-3})/(4^{1-x)}=1 ?

The answer to (2^{x-3})/(4^{1-x)}=1 is x= 5/3

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(2^{x-3})/(4^{1-x)}=1

\frac{2 ^{x - 3}}{4 ^{1 - x}} = 1

x = \frac{5}{3}

Decimal Notation

x = 1.66666 \dots

Solution steps

\frac{2 ^{x - 3}}{4 ^{1 - x}} = 1

Apply exponent rules

3 (x - 3) = - 4

Solve

3 (x - 3) = - 4 : x = \frac{5}{3}

x = \frac{5}{3}

Verify Solutions:

x = \frac{5}{3}

True

The solution is

x = \frac{5}{3}

625 (5^{x - 2}) - 5^{x} = 120

12 \cdot 1.1 7^{t} = 56

5 = 8^{x}

e^{x} + e^{- x} = 2 e

3^{(6 + 3 x)} = \frac{1}{27}

What is the answer to (2^{x-3})/(4^{1-x)}=1 ?
The answer to (2^{x-3})/(4^{1-x)}=1 is x= 5/3
Solve for x: (2^{x-3})/(4^{1-x)}=1
The solution is x= 5/3