What is the answer to 3^{5x+8}=7^{2x-4} ?

The answer to 3^{5x+8}=7^{2x-4} is x=(-4ln(7)-8ln(3))/(5ln(3)-2ln(7))

Solve for x: 3^{5x+8}=7^{2x-4}

The solution is x=(-4ln(7)-8ln(3))/(5ln(3)-2ln(7))

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3^{5 x + 8} = 7^{2 x - 4}

x = \frac{- 4 ln ( 7 ) - 8 ln ( 3 )}{5 ln ( 3 ) - 2 ln ( 7 )}

Decimal Notation

x = - 10.34980 \dots

Solution steps

3^{5 x + 8} = 7^{2 x - 4}

Apply exponent rules

(5 x + 8) ln (3) = (2 x - 4) ln (7)

Solve

(5 x + 8) ln (3) = (2 x - 4) ln (7) : x = \frac{- 4 ln ( 7 ) - 8 ln ( 3 )}{5 ln ( 3 ) - 2 ln ( 7 )}

x = \frac{- 4 ln ( 7 ) - 8 ln ( 3 )}{5 ln ( 3 ) - 2 ln ( 7 )}

4 - 2 e^{x + 1} = - 12

3^{x + 2} = 9

0. 1^{x} = 1000

2^{x} 3^{x - 2} = 4

x^{2} e^{x} - 6 x e^{x} - 7 e^{x} = 0

What is the answer to 3^{5x+8}=7^{2x-4} ?
The answer to 3^{5x+8}=7^{2x-4} is x=(-4ln(7)-8ln(3))/(5ln(3)-2ln(7))
Solve for x: 3^{5x+8}=7^{2x-4}
The solution is x=(-4ln(7)-8ln(3))/(5ln(3)-2ln(7))