What is the answer to 15^{-x+2}=11^{-7x} ?

The answer to 15^{-x+2}=11^{-7x} is x=-(2ln(15))/(-ln(15)+7ln(11))

Solve for x: 15^{-x+2}=11^{-7x}

The solution is x=-(2ln(15))/(-ln(15)+7ln(11))

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1 5^{- x + 2} = 1 1^{- 7 x}

x = - \frac{2 ln ( 15 )}{- ln ( 15 ) + 7 ln ( 11 )}

Decimal Notation

x = - 0.38474 \dots

Solution steps

1 5^{- x + 2} = 1 1^{- 7 x}

Apply exponent rules

(- x + 2) ln (15) = - 7 x ln (11)

Solve

(- x + 2) ln (15) = - 7 x ln (11) : x = - \frac{2 ln ( 15 )}{- ln ( 15 ) + 7 ln ( 11 )}

x = - \frac{2 ln ( 15 )}{- ln ( 15 ) + 7 ln ( 11 )}

9 = 2^{t}

1 8^{x} = 3

e^{2 x + 3} = 0

e^{2 - 3 x} = 4

3^{x} - 6 (3)^{x} - 27 = 0

What is the answer to 15^{-x+2}=11^{-7x} ?
The answer to 15^{-x+2}=11^{-7x} is x=-(2ln(15))/(-ln(15)+7ln(11))
Solve for x: 15^{-x+2}=11^{-7x}
The solution is x=-(2ln(15))/(-ln(15)+7ln(11))