What is (m^3-n^3)/(m-n) ?

The solution to (m^3-n^3)/(m-n) is m^2+mn+n^2

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simplify (m^3-n^3)/(m-n)

simplify

\frac{m ^{3} - n ^{3}}{m - n}

m^{2} + mn + n^{2}

Solution steps

\frac{m ^{3} - n ^{3}}{m - n}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

m^{3} - n^{3} = (m - n) (m^{2} + mn + n^{2})

= \frac{( m - n ) ( m ^{2} + mn + n ^{2} )}{m - n}

Cancel the common factor:

m - n

= m^{2} + mn + n^{2}

7 x - 3 = x + 3

(\frac{125}{8})^{\frac{2}{3}}

16 9^{\frac{1}{2}}

1.6 = \frac{f - 17.08}{17.08}

- 5 \leq \frac{- 3 x + 1}{4} \leq 15