What is the answer to 4*3^{2x}=5^x ?

The answer to 4*3^{2x}=5^x is x=-(2ln(2))/(2ln(3)-ln(5))

Solve for x: 4*3^{2x}=5^x

The solution is x=-(2ln(2))/(2ln(3)-ln(5))

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4 \cdot 3^{2 x} = 5^{x}

x = - \frac{2 ln ( 2 )}{2 ln ( 3 ) - ln ( 5 )}

Decimal Notation

x = - 2.35849 \dots

Solution steps

4 \cdot 3^{2 x} = 5^{x}

Apply exponent rules

ln (4) + 2 x ln (3) = x ln (5)

Solve

ln (4) + 2 x ln (3) = x ln (5) : x = - \frac{2 ln ( 2 )}{2 ln ( 3 ) - ln ( 5 )}

x = - \frac{2 ln ( 2 )}{2 ln ( 3 ) - ln ( 5 )}

125 = 2 5^{x + 3}

x^{2} e^{x} - 3 x e^{x} + 2 e^{x} = 0

3^{x + 1} = \frac{1 ^{x}}{3}

x, 3^{2 x} = g^{3 - x}

3 \cdot 2^{- x} = 2 \cdot 3^{x}

What is the answer to 4*3^{2x}=5^x ?
The answer to 4*3^{2x}=5^x is x=-(2ln(2))/(2ln(3)-ln(5))
Solve for x: 4*3^{2x}=5^x
The solution is x=-(2ln(2))/(2ln(3)-ln(5))