What is the answer to 3*4^2=2^{3x-5} ?

The answer to 3*4^2=2^{3x-5} is x=(ln(1536))/(3ln(2))

Solve for x: 3*4^2=2^{3x-5}

The solution is x=(ln(1536))/(3ln(2))

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3 \cdot 4^{2} = 2^{3 x - 5}

x = \frac{ln ( 1536 )}{3 ln ( 2 )}

Decimal Notation

x = 3.52832 \dots

Solution steps

3 \cdot 4^{2} = 2^{3 x - 5}

Apply exponent rules

ln (3 \cdot 2^{2 \cdot 2}) = (3 x - 5) ln (2)

Solve

ln (3 \cdot 2^{2 \cdot 2}) = (3 x - 5) ln (2) : x = \frac{ln ( 1536 )}{3 ln ( 2 )}

x = \frac{ln ( 1536 )}{3 ln ( 2 )}

2^{5 x} = 128

e^{x^{2}} = \frac{1}{9}

2^{x - 5} = 32

0 = e^{x \cdot 34}

8^{x} - 2 (4^{x}) - 8 (2^{x}) = 0

What is the answer to 3*4^2=2^{3x-5} ?
The answer to 3*4^2=2^{3x-5} is x=(ln(1536))/(3ln(2))
Solve for x: 3*4^2=2^{3x-5}
The solution is x=(ln(1536))/(3ln(2))