What is the answer to (1/8)^{2x+1}=64 ?

The answer to (1/8)^{2x+1}=64 is x=-3/2

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(1/8)^{2x+1}=64

(\frac{1}{8})^{2 x + 1} = 64

x = - \frac{3}{2}

Decimal Notation

x = - 1.5

Solution steps

(\frac{1}{8})^{2 x + 1} = 64

Apply exponent rules

- (2 x + 1) = 2

Solve

- (2 x + 1) = 2 : x = - \frac{3}{2}

x = - \frac{3}{2}

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