What is the answer to 25^{2x+1}=(1/9)^{3x} ?

The answer to 25^{2x+1}=(1/9)^{3x} is x=-(ln(5))/(ln(675))

Solve for x: 25^{2x+1}=(1/9)^{3x}

The solution is x=-(ln(5))/(ln(675))

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2 5^{2 x + 1} = (\frac{1}{9})^{3 x}

x = - \frac{ln ( 5 )}{ln ( 675 )}

Decimal Notation

x = - 0.24704 \dots

Solution steps

2 5^{2 x + 1} = (\frac{1}{9})^{3 x}

Apply exponent rules

(2 x + 1) ln (25) = 3 x ln (\frac{1}{9})

Solve

(2 x + 1) ln (25) = 3 x ln (\frac{1}{9}) : x = - \frac{ln ( 5 )}{ln ( 675 )}

x = - \frac{ln ( 5 )}{ln ( 675 )}

2 x + 4^{x} = 6

4^{- 2 x + 2} = 1 6^{x - 3}

2 5^{x + 3} = 5^{x + 2}

2^{4 x} = 2^{2 x - 6}

4^{x} = 2^{x} \cdot 2^{x}

What is the answer to 25^{2x+1}=(1/9)^{3x} ?
The answer to 25^{2x+1}=(1/9)^{3x} is x=-(ln(5))/(ln(675))
Solve for x: 25^{2x+1}=(1/9)^{3x}
The solution is x=-(ln(5))/(ln(675))