What is the answer to 8^{-1}*2^{(2x+1)}=64 ?

The answer to 8^{-1}*2^{(2x+1)}=64 is x=4

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8^{-1}*2^{(2x+1)}=64

8^{- 1} \cdot 2^{(2 x + 1)} = 64

x = 4

Solution steps

8^{- 1} \cdot 2^{(2 x + 1)} = 64

Divide both sides by

8^{- 1}

2^{2 x + 1} = \frac{64}{8 ^{- 1}}

Simplify

\frac{64}{8 ^{- 1}} : 512

2^{2 x + 1} = 512

Apply exponent rules

2 x + 1 = 9

Solve

2 x + 1 = 9 : x = 4

x = 4

6^{x - 3} = 2^{x}

4^{x} = 2^{x + 3}

7^{- 2 x - 4} = 49

- 50 (1 - 2^{x}) = 123723

4^{x} (1 - 4^{- 2 x}) = 3

What is the answer to 8^{-1}*2^{(2x+1)}=64 ?
The answer to 8^{-1}*2^{(2x+1)}=64 is x=4
Solve for x: 8^{-1}*2^{(2x+1)}=64
The solution is x=4