What is the answer to 7^{2x-3}=14 ?

The answer to 7^{2x-3}=14 is x=(ln(4802))/(2ln(7))

Solve for x: 7^{2x-3}=14

The solution is x=(ln(4802))/(2ln(7))

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7^{2 x - 3} = 14

x = \frac{ln ( 4802 )}{2 ln ( 7 )}

Decimal Notation

x = 2.17810 \dots

Solution steps

7^{2 x - 3} = 14

Apply exponent rules

(2 x - 3) ln (7) = ln (14)

Solve

(2 x - 3) ln (7) = ln (14) : x = \frac{ln ( 4802 )}{2 ln ( 7 )}

x = \frac{ln ( 4802 )}{2 ln ( 7 )}

\frac{50}{1 + e ^{- x}} = 3

100 - 100 (\frac{1}{4})^{x} = 70

4 (5^{x}) = 10

5^{x + 1} + 4 (5^{x}) = 45

12 5^{2 x + 5} = 62 5^{x + 4}

What is the answer to 7^{2x-3}=14 ?
The answer to 7^{2x-3}=14 is x=(ln(4802))/(2ln(7))
Solve for x: 7^{2x-3}=14
The solution is x=(ln(4802))/(2ln(7))