What is the answer to 6=12*5^{-k^{20}} ?

The answer to 6=12*5^{-k^{20}} is k=\sqrt[20]{(ln(2))/(ln(5))},k=-\sqrt[20]{(ln(2))/(ln(5))}

Solve for k: 6=12*5^{-k^{20}}

The solution is k=\sqrt[20]{(ln(2))/(ln(5))},k=-\sqrt[20]{(ln(2))/(ln(5))}

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6 = 12 \cdot 5^{- k^{20}}

Decimal Notation

k = 0.95875 \dots, k = - 0.95875 \dots

Solution steps

6 = 12 \cdot 5^{- k^{20}}

Switch sides

12 \cdot 5^{- k^{20}} = 6

Divide both sides by

12

5^{- k^{20}} = \frac{1}{2}

Apply exponent rules

- k^{20} ln (5) = ln (\frac{1}{2})

Solve

7^{- x} \cdot 7^{- x} = 343

0 = 10 e^{0.002 x}

6^{4 x - 4} = 1

e^{x^{2}} = e^{x} (e^{x - 1})^{2}

\frac{1}{2 ^{x}} = 8

What is the answer to 6=12*5^{-k^{20}} ?
The answer to 6=12*5^{-k^{20}} is k=\sqrt[20]{(ln(2))/(ln(5))},k=-\sqrt[20]{(ln(2))/(ln(5))}
Solve for k: 6=12*5^{-k^{20}}
The solution is k=\sqrt[20]{(ln(2))/(ln(5))},k=-\sqrt[20]{(ln(2))/(ln(5))}