What is the answer to 49^{x+3}=7^{x^2-3x+8} ?

The answer to 49^{x+3}=7^{x^2-3x+8} is x=(5+sqrt(17))/2 ,x=(5-sqrt(17))/2

Solve for x: 49^{x+3}=7^{x^2-3x+8}

The solution is x=(5+sqrt(17))/2 ,x=(5-sqrt(17))/2

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4 9^{x + 3} = 7^{x^{2} - 3 x + 8}

x = \frac{5 + 17}{2}, x = \frac{5 - 17}{2}

Decimal Notation

x = 4.56155 \dots, x = 0.43844 \dots

Solution steps

4 9^{x + 3} = 7^{x^{2} - 3 x + 8}

Apply exponent rules

2 (x + 3) = x^{2} - 3 x + 8

Solve

2 (x + 3) = x^{2} - 3 x + 8 : x = \frac{5 + 17}{2}, x = \frac{5 - 17}{2}

x = \frac{5 + 17}{2}, x = \frac{5 - 17}{2}

8^{x} = 360000000

3^{x + 1} + 3^{x - 1} = 90

7^{q} = 49

2000 = 1000 e^{0.09 x}

4^{x} = 1 6^{2 x + 9}

What is the answer to 49^{x+3}=7^{x^2-3x+8} ?
The answer to 49^{x+3}=7^{x^2-3x+8} is x=(5+sqrt(17))/2 ,x=(5-sqrt(17))/2
Solve for x: 49^{x+3}=7^{x^2-3x+8}
The solution is x=(5+sqrt(17))/2 ,x=(5-sqrt(17))/2