What is the answer to 4/((2^x))=98 ?

The answer to 4/((2^x))=98 is x=-(ln(49/2))/(ln(2))

Solve for x: 4/((2^x))=98

The solution is x=-(ln(49/2))/(ln(2))

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\frac{4}{( 2 ^{x} )} = 98

x = - \frac{ln ( \frac{49}{2} )}{ln ( 2 )}

Decimal Notation

x = - 4.61470 \dots

Solution steps

\frac{4}{( 2 ^{x} )} = 98

Apply exponent rules

- x ln (2) = ln (\frac{49}{2})

Solve

- x ln (2) = ln (\frac{49}{2}) : x = - \frac{ln ( \frac{49}{2} )}{ln ( 2 )}

x = - \frac{ln ( \frac{49}{2} )}{ln ( 2 )}

Verify Solutions:

x = - \frac{ln ( \frac{49}{2} )}{ln ( 2 )}

True

The solution is

x = - \frac{ln ( \frac{49}{2} )}{ln ( 2 )}

N = 0.892 e^{0.0091 t}

5^{x + 2} = 1

2^{x} - 12 \cdot 2^{x} + 32 = 0

15.7 (0.98)^{x} = 11 (0.99)^{x}

4^{x} (5^{2} x) = 10

What is the answer to 4/((2^x))=98 ?
The answer to 4/((2^x))=98 is x=-(ln(49/2))/(ln(2))
Solve for x: 4/((2^x))=98
The solution is x=-(ln(49/2))/(ln(2))