What is the answer to 3^{x^2}=9^{-x+12} ?

The answer to 3^{x^2}=9^{-x+12} is x=4,x=-6

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3^{x^2}=9^{-x+12}

3^{x^{2}} = 9^{- x + 12}

x = 4, x = - 6

Solution steps

3^{x^{2}} = 9^{- x + 12}

Apply exponent rules

x^{2} = 2 (- x + 12)

Solve

x^{2} = 2 (- x + 12) : x = 4, x = - 6

x = 4, x = - 6

3^{- x} = \frac{1}{3 ^{x}}

4^{2 x} - 68 \cdot 4^{x} + 256 = 0

x, 4^{3 x} = 4^{x - 1}

3 = 5^{x}

x, 2^{x + 3^{y}} = 11

What is the answer to 3^{x^2}=9^{-x+12} ?
The answer to 3^{x^2}=9^{-x+12} is x=4,x=-6
Solve for x: 3^{x^2}=9^{-x+12}
The solution is x=4,x=-6