What is the answer to solvefor x,7e^{1x+2.3}=136 ?

The answer to solvefor x,7e^{1x+2.3}=136 is x=ln(136/7)-2.3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,7e^{1x+2.3}=136

solve for

x, 7 e^{1 x + 2.3} = 136

x = ln (\frac{136}{7}) - 2.3

Solution steps

7 e^{1 \cdot x + 2.3} = 136

Divide both sides by

7

e^{1 x + 2.3} = \frac{136}{7}

Apply exponent rules

1 \cdot x + 2.3 = ln (\frac{136}{7})

Solve

1 \cdot x + 2.3 = ln (\frac{136}{7}) : x = ln (\frac{136}{7}) - 2.3

x = ln (\frac{136}{7}) - 2.3

2^{x} = e^{x + 2}

37.5 = 3^{n}

3^{- 2 b} = \frac{1}{27}

4^{2 x} - 2 (4^{x}) - 8 = 0

y, x = 1 0^{y} + 4

What is the answer to solvefor x,7e^{1x+2.3}=136 ?
The answer to solvefor x,7e^{1x+2.3}=136 is x=ln(136/7)-2.3