What is the answer to 1100=250*2^{1/t} ?

The answer to 1100=250*2^{1/t} is t=(ln(2))/(ln(22/5))

Solve for t: 1100=250*2^{1/t}

The solution is t=(ln(2))/(ln(22/5))

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1100 = 250 \cdot 2^{\frac{1}{t}}

t = \frac{ln ( 2 )}{ln ( \frac{22}{5} )}

Solution steps

1100 = 250 \cdot 2^{\frac{1}{t}}

Switch sides

250 \cdot 2^{\frac{1}{t}} = 1100

Divide both sides by

250

2^{\frac{1}{t}} = \frac{22}{5}

Apply exponent rules

\frac{1}{t} ln (2) = ln (\frac{22}{5})

Solve

\frac{1}{t} ln (2) = ln (\frac{22}{5}) : t = \frac{ln ( 2 )}{ln ( \frac{22}{5} )}

t = \frac{ln ( 2 )}{ln ( \frac{22}{5} )}

10 = 200 e^{- 0.347 x}

m e^{m x} + 3 e^{m x} = 0

22 = 200 \cdot (0.8)^{t}

4^{x + 1} \cdot (- 1) = - 4^{x + 1}

\frac{2 7 ^{4} 9 ^{- 6}}{81} = 3^{x}

What is the answer to 1100=250*2^{1/t} ?
The answer to 1100=250*2^{1/t} is t=(ln(2))/(ln(22/5))
Solve for t: 1100=250*2^{1/t}
The solution is t=(ln(2))/(ln(22/5))