What is the answer to 4000=2^x ?

The answer to 4000=2^x is x=(ln(4000))/(ln(2))

Solve for x: 4000=2^x

The solution is x=(ln(4000))/(ln(2))

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4000 = 2^{x}

x = \frac{ln ( 4000 )}{ln ( 2 )}

Solution steps

4000 = 2^{x}

Apply exponent rules

ln (4000) = x ln (2)

Solve

ln (4000) = x ln (2) : x = \frac{ln ( 4000 )}{ln ( 2 )}

x = \frac{ln ( 4000 )}{ln ( 2 )}

3 \cdot 2^{3 x} = 7 \cdot 3^{3 x - 2}

(3^{2 x + 1} + 9) = (3^{x + 3} + 3^{x})

3^{x} + 3^{x - 1} + 3^{x - 2} = 13

e^{2 x} - 2 e^{x} = 1

1 6^{x} = 8^{2 x + 3}