What is the answer to log_{10}(43)=4.2^x ?

The answer to log_{10}(43)=4.2^x is x=(ln(log_{10}(43)))/(ln(4.2))

Solve for x: log_{10}(43)=4.2^x

The solution is x=(ln(log_{10}(43)))/(ln(4.2))

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lo g_{10} (43) = 4. 2^{x}

x = \frac{ln ( lo g _{10} ( 43 ) )}{ln ( 4.2 )}

Solution steps

lo g_{10} (43) = 4. 2^{x}

Apply exponent rules

ln (lo g_{10} (43)) = x ln (4.2)

Solve

ln (lo g_{10} (43)) = x ln (4.2) : x = \frac{ln ( lo g _{10} ( 43 ) )}{ln ( 4.2 )}

x = \frac{ln ( lo g _{10} ( 43 ) )}{ln ( 4.2 )}

2^{x} - 2^{2 - x} = 0

e^{- 8 n - 9} = 36.5

1 6^{(- r - 1)} = \frac{1}{4}

e^{- 2 t} + 6 = 5 e^{- t}

5^{x} = 40

What is the answer to log_{10}(43)=4.2^x ?
The answer to log_{10}(43)=4.2^x is x=(ln(log_{10}(43)))/(ln(4.2))
Solve for x: log_{10}(43)=4.2^x
The solution is x=(ln(log_{10}(43)))/(ln(4.2))