What are the solutions to the equation x^2+8x-55=10 ?

The solutions to the equation x^2+8x-55=10 are x=5,x=-13

Find the zeros of x^2+8x-55=10

The zeros of x^2+8x-55=10 are x=5,x=-13

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x^{2} + 8 x - 55 = 10

x = 5, x = - 13

Solution steps

x^{2} + 8 x - 55 = 10

Move

10

to the left side

x^{2} + 8 x - 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 65 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 65) = 18

x_{1, 2} = \frac{- 8 \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 18}{2 \cdot 1}, x_{2} = \frac{- 8 - 18}{2 \cdot 1}

x = \frac{- 8 + 18}{2 \cdot 1} : 5

x = \frac{- 8 - 18}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = 5, x = - 13

4 z^{2} - 8 z + 5 = 2

\frac{1}{x + h + 1} - \frac{1}{x + 1}

lo g_{3} (64)

1 0^{2} + 6^{2} = x^{2}

- 2 \cdot - 50

What are the solutions to the equation x^2+8x-55=10 ?
The solutions to the equation x^2+8x-55=10 are x=5,x=-13
Find the zeros of x^2+8x-55=10
The zeros of x^2+8x-55=10 are x=5,x=-13